[rockstar]

Hi all,

Could anyone tell me what's wrong with my script below?

echo "please enter name"
read name

echo "Please enter new new group id"
echo answer

nawk -F: -v user="$name" '$1 == user{print $1 ":" $4="$answer"}' $PASSWD

I tried to change a group id of specific user

please help

[eggi]

Hey There,

The $4=$answer probably isnt' resolving in awk,

you could add an extra -v

-v answer=$answer

preceding it or use double quotes around your awk statement,a lthough that will probably cause issues with the awk variables, so:

 nawk -F: -v answer=$answer -v user="$name" '$1 == user{print $1 ":" $4=answer}' $PASSWD

Might work.

best wishes,

Mike

[rockstar]

it doesn not

complaining as illegal statement

[eggi]

Hey there,

My fault - used awk.

It won't work with nawk either, but this will - same thing - different order:

nawk -F: -v answer=$answer -v user="$name" '{ if ( $1 == user ) print $1 ":" answer }' $PASSWD

Best wishes,

Mike

[rockstar]

Hi eggi,

It works..

But my question is how do i know if answer is replacing $4 field?

When i run the script as you mentioned, the output is blah:XXX

[rockstar]

Hi Eggi,

don't worry..

I managed to get it on the right field by using:


nawk -F: -v answer=$answer -v user="$name" '{ if ( $1 == user ) print $1 ":" $2 ":" $3 ":" answer }' $PASSWD

[rockstar]

Thank you for helping eggie

[eggi]

Glad I could

Take care,

Mike